What are the solutions to the equation x^2-20x+36=-7x ?

The solutions to the equation x^2-20x+36=-7x are x=9,x=4

Find the zeros of x^2-20x+36=-7x

The zeros of x^2-20x+36=-7x are x=9,x=4

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x^{2} - 20 x + 36 = - 7 x

x = 9, x = 4

Solution steps

x^{2} - 20 x + 36 = - 7 x

Move

7 x

to the left side

x^{2} - 13 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 36 = 5

x_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 1}

x = \frac{- ( - 13 ) + 5}{2 \cdot 1} : 9

x = \frac{- ( - 13 ) - 5}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 9, x = 4

y, x^{2} - x y + y^{2} = 5 x + 6 y - 13

25 x^{2} - 25 x = - 6

y, x^{2} + 4 x y + 16 y^{2} = 27

(x - 1)^{2} = - (x + 1)^{2} + 4

y^{2} - 2 y + (1 + 4 π^{2}) = 0

What are the solutions to the equation x^2-20x+36=-7x ?
The solutions to the equation x^2-20x+36=-7x are x=9,x=4
Find the zeros of x^2-20x+36=-7x
The zeros of x^2-20x+36=-7x are x=9,x=4