What are the solutions to the equation 4t^2-9t+2=0 ?

The solutions to the equation 4t^2-9t+2=0 are t=2,t= 1/4

Find the zeros of 4t^2-9t+2=0

The zeros of 4t^2-9t+2=0 are t=2,t= 1/4

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4 t^{2} - 9 t + 2 = 0

t = 2, t = \frac{1}{4}

Decimal Notation

t = 2, t = 0.25

Solution steps

4 t^{2} - 9 t + 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 2 = 7

t_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 4}, t_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 4}

t = \frac{- ( - 9 ) + 7}{2 \cdot 4} : 2

t = \frac{- ( - 9 ) - 7}{2 \cdot 4} : \frac{1}{4}

The solutions to the quadratic equation are:

t = 2, t = \frac{1}{4}

a, (a + b)^{3} = a^{3} + b^{3}

x, x^{2} - 5 k x - 50 k^{2} = 0

(m - 2) x^{2} - 2 m x + 3 m = 0

x = - 6 x^{2} + 8 x + 4

x^{2} - 3 x + \frac{1}{4} = 0

What are the solutions to the equation 4t^2-9t+2=0 ?
The solutions to the equation 4t^2-9t+2=0 are t=2,t= 1/4
Find the zeros of 4t^2-9t+2=0
The zeros of 4t^2-9t+2=0 are t=2,t= 1/4