What are the solutions to the equation h^2+400h-125000=0 ?

The solutions to the equation h^2+400h-125000=0 are h=50(sqrt(66)-4),h=-50(4+sqrt(66))

Find the zeros of h^2+400h-125000=0

The zeros of h^2+400h-125000=0 are h=50(sqrt(66)-4),h=-50(4+sqrt(66))

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h^{2} + 400 h - 125000 = 0

h = 50 (66 - 4), h = - 50 (4 + 66)

Decimal Notation

h = 206.20192 \dots, h = - 606.20192 \dots

Solution steps

h^{2} + 400 h - 125000 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 \cdot 1 \cdot ( - 125000 )}{2 \cdot 1}

40 0^{2} - 4 \cdot 1 \cdot (- 125000) = 10066

h_{1, 2} = \frac{- 400 \pm 100 66}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- 400 + 100 66}{2 \cdot 1}, h_{2} = \frac{- 400 - 100 66}{2 \cdot 1}

h = \frac{- 400 + 100 66}{2 \cdot 1} : 50 (66 - 4)

h = \frac{- 400 - 100 66}{2 \cdot 1} : - 50 (4 + 66)

The solutions to the quadratic equation are:

h = 50 (66 - 4), h = - 50 (4 + 66)

u^{2} = - 16

3 x^{2} + 5 x - 322 = 0

(7 x + 6)^{2} = 16

(- 0.2) x^{2} + 80 x - 3.95 = 0

2 x^{2} - 27 x + 36 = 0

What are the solutions to the equation h^2+400h-125000=0 ?
The solutions to the equation h^2+400h-125000=0 are h=50(sqrt(66)-4),h=-50(4+sqrt(66))
Find the zeros of h^2+400h-125000=0
The zeros of h^2+400h-125000=0 are h=50(sqrt(66)-4),h=-50(4+sqrt(66))