What are the solutions to the equation -9x^2+18x+35=0 ?

The solutions to the equation -9x^2+18x+35=0 are x=-(-3+2sqrt(11))/3 ,x=(3+2sqrt(11))/3

Find the zeros of -9x^2+18x+35=0

The zeros of -9x^2+18x+35=0 are x=-(-3+2sqrt(11))/3 ,x=(3+2sqrt(11))/3

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- 9 x^{2} + 18 x + 35 = 0

x = - \frac{- 3 + 2 11}{3}, x = \frac{3 + 2 11}{3}

Decimal Notation

x = - 1.21108 \dots, x = 3.21108 \dots

Solution steps

- 9 x^{2} + 18 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 9 ) \cdot 35}{2 ( - 9 )}

1 8^{2} - 4 (- 9) \cdot 35 = 1211

x_{1, 2} = \frac{- 18 \pm 12 11}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 18 + 12 11}{2 ( - 9 )}, x_{2} = \frac{- 18 - 12 11}{2 ( - 9 )}

x = \frac{- 18 + 12 11}{2 ( - 9 )} : - \frac{- 3 + 2 11}{3}

x = \frac{- 18 - 12 11}{2 ( - 9 )} : \frac{3 + 2 11}{3}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 2 11}{3}, x = \frac{3 + 2 11}{3}

7 x^{2} + 40 x = 12

(2 x - 5)^{2} - (x - 6)^{2} = 5

3 x^{2} - 6 x + 14

2 x^{2} - 36 x = - 160

(h - 2)^{2} = 9

What are the solutions to the equation -9x^2+18x+35=0 ?
The solutions to the equation -9x^2+18x+35=0 are x=-(-3+2sqrt(11))/3 ,x=(3+2sqrt(11))/3
Find the zeros of -9x^2+18x+35=0
The zeros of -9x^2+18x+35=0 are x=-(-3+2sqrt(11))/3 ,x=(3+2sqrt(11))/3