What are the solutions to the equation 13x^2-26x+12=0 ?

The solutions to the equation 13x^2-26x+12=0 are x=(13+sqrt(13))/(13),x=(13-sqrt(13))/(13)

Find the zeros of 13x^2-26x+12=0

The zeros of 13x^2-26x+12=0 are x=(13+sqrt(13))/(13),x=(13-sqrt(13))/(13)

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13 x^{2} - 26 x + 12 = 0

x = \frac{13 + 13}{13}, x = \frac{13 - 13}{13}

Decimal

x = 1.27735 \dots, x = 0.72264 \dots

Solution steps

13 x^{2} - 26 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 13 \cdot 12}{2 \cdot 13}

(- 26)^{2} - 4 \cdot 13 \cdot 12 = 213

x_{1, 2} = \frac{- ( - 26 ) \pm 2 13}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 2 13}{2 \cdot 13}, x_{2} = \frac{- ( - 26 ) - 2 13}{2 \cdot 13}

x = \frac{- ( - 26 ) + 2 13}{2 \cdot 13} : \frac{13 + 13}{13}

x = \frac{- ( - 26 ) - 2 13}{2 \cdot 13} : \frac{13 - 13}{13}

The solutions to the quadratic equation are:

x = \frac{13 + 13}{13}, x = \frac{13 - 13}{13}

12 x^{2} = 23

y, x^{2} + y^{2} - 8 y + 10 y + 30 = 0

y, x^{2} + y^{2} - 2 x + y + 6 = 0

x (2 x - 11) = 12

x^{2} - 50 x - 5000 = 0

What are the solutions to the equation 13x^2-26x+12=0 ?
The solutions to the equation 13x^2-26x+12=0 are x=(13+sqrt(13))/(13),x=(13-sqrt(13))/(13)
Find the zeros of 13x^2-26x+12=0
The zeros of 13x^2-26x+12=0 are x=(13+sqrt(13))/(13),x=(13-sqrt(13))/(13)