What are the solutions to the equation factor 21c^2-16c-6=1-2c ?

The solutions to the equation factor 21c^2-16c-6=1-2c are c=-1/3 ,c=1

Find the zeros of factor 21c^2-16c-6=1-2c

The zeros of factor 21c^2-16c-6=1-2c are c=-1/3 ,c=1

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21 c^{2} - 16 c - 6 = 1 - 2 c

c = - \frac{1}{3}, c = 1

Decimal Notation

c = - 0.33333 \dots, c = 1

Solution steps

21 c^{2} - 16 c - 6 = 1 - 2 c

Move

2 c

to the left side

21 c^{2} - 14 c - 6 = 1

Move

1

to the left side

21 c^{2} - 14 c - 7 = 0

Factor

21 c^{2} - 14 c - 7 : 7 (3 c + 1) (c - 1)

7 (3 c + 1) (c - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 c + 1 = 0 or c - 1 = 0

Solve

3 c + 1 = 0 : c = - \frac{1}{3}

Solve

c - 1 = 0 : c = 1

The solutions to the quadratic equation are:

c = - \frac{1}{3}, c = 1

- \frac{40}{3} = - \frac{10}{3} x^{2}

(x - 11)^{2} - 81 = 0

4800008 x^{2} = 0.0233 - x

d^{2} - 12 d - 14 = - 6 d

12 y^{2} + 19 y + 5 = 0

What are the solutions to the equation factor 21c^2-16c-6=1-2c ?
The solutions to the equation factor 21c^2-16c-6=1-2c are c=-1/3 ,c=1
Find the zeros of factor 21c^2-16c-6=1-2c
The zeros of factor 21c^2-16c-6=1-2c are c=-1/3 ,c=1