What are the solutions to the equation 5x^2-x=4 ?

The solutions to the equation 5x^2-x=4 are x=1,x=-4/5

Find the zeros of 5x^2-x=4

The zeros of 5x^2-x=4 are x=1,x=-4/5

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5 x^{2} - x = 4

x = 1, x = - \frac{4}{5}

Decimal Notation

x = 1, x = - 0.8

Solution steps

5 x^{2} - x = 4

Move

4

to the left side

5 x^{2} - x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 4) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 5}

x = \frac{- ( - 1 ) + 9}{2 \cdot 5} : 1

x = \frac{- ( - 1 ) - 9}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{5}

c^{2} + 3^{2} = 7^{2}

7 (\frac{2 ( 3 n - 5 ) - 8 + 1}{6}) - 4 = 73

- 4 - 3 m + m^{2}

\frac{3 π}{2} \cdot 2

6 x^{2} - 16 x - 6

What are the solutions to the equation 5x^2-x=4 ?
The solutions to the equation 5x^2-x=4 are x=1,x=-4/5
Find the zeros of 5x^2-x=4
The zeros of 5x^2-x=4 are x=1,x=-4/5