What are the solutions to the equation roots x^2-6x+16 ?

The solutions to the equation roots x^2-6x+16 are x=3+sqrt(7)i,x=3-sqrt(7)i

Find the zeros of roots x^2-6x+16

The zeros of roots x^2-6x+16 are x=3+sqrt(7)i,x=3-sqrt(7)i

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roots

x^{2} - 6 x + 16

x = 3 + 7 i, x = 3 - 7 i

Solution steps

x^{2} - 6 x + 16

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 6 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 16 : 27 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 1} : 3 + 7 i

x = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 1} : 3 - 7 i

The solutions to the quadratic equation are:

x = 3 + 7 i, x = 3 - 7 i

64 x^{2} - 36 = 0

(s + 1)^{2} + 4

9 (x + 9)^{2} - 36 = 0

(2 x - 1) (3 x + 1) = 0

12 x^{2} - 24 x - 4 = 0

What are the solutions to the equation roots x^2-6x+16 ?
The solutions to the equation roots x^2-6x+16 are x=3+sqrt(7)i,x=3-sqrt(7)i
Find the zeros of roots x^2-6x+16
The zeros of roots x^2-6x+16 are x=3+sqrt(7)i,x=3-sqrt(7)i