What are the solutions to the equation 0=-4.9t^2-44.1t+176.4 ?

The solutions to the equation 0=-4.9t^2-44.1t+176.4 are t=-12,t=3

Find the zeros of 0=-4.9t^2-44.1t+176.4

The zeros of 0=-4.9t^2-44.1t+176.4 are t=-12,t=3

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0 = - 4.9 t^{2} - 44.1 t + 176.4

t = - 12, t = 3

Solution steps

0 = - 4.9 t^{2} - 44.1 t + 176.4

Multiply both sides by

10

0 = - 49 t^{2} - 441 t + 1764

Switch sides

- 49 t^{2} - 441 t + 1764 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 441 ) \pm ( - 441 ) ^{2} - 4 ( - 49 ) \cdot 1764}{2 ( - 49 )}

(- 441)^{2} - 4 (- 49) \cdot 1764 = 735

t_{1, 2} = \frac{- ( - 441 ) \pm 735}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- ( - 441 ) + 735}{2 ( - 49 )}, t_{2} = \frac{- ( - 441 ) - 735}{2 ( - 49 )}

t = \frac{- ( - 441 ) + 735}{2 ( - 49 )} : - 12

t = \frac{- ( - 441 ) - 735}{2 ( - 49 )} : 3

The solutions to the quadratic equation are:

t = - 12, t = 3

- 16 t^{2} + 34 t + 42 = 0

x^{2} - 8 (x + 3) = + 4 x - 45

2 x^{2} + 3 x - 54 = 0

- 16 x^{2} - 8 x + 64 = 0

x^{2} + 22 x + 116.5 = 0

What are the solutions to the equation 0=-4.9t^2-44.1t+176.4 ?
The solutions to the equation 0=-4.9t^2-44.1t+176.4 are t=-12,t=3
Find the zeros of 0=-4.9t^2-44.1t+176.4
The zeros of 0=-4.9t^2-44.1t+176.4 are t=-12,t=3