What are the solutions to the equation x^2+18x+27=8x+3 ?

The solutions to the equation x^2+18x+27=8x+3 are x=-4,x=-6

Find the zeros of x^2+18x+27=8x+3

The zeros of x^2+18x+27=8x+3 are x=-4,x=-6

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x^{2} + 18 x + 27 = 8 x + 3

x = - 4, x = - 6

Solution steps

x^{2} + 18 x + 27 = 8 x + 3

Move

3

to the left side

x^{2} + 18 x + 24 = 8 x

Move

8 x

to the left side

x^{2} + 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 2}{2 \cdot 1}

x = \frac{- 10 + 2}{2 \cdot 1} : - 4

x = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 4, x = - 6

12 a^{2} - 22 a - 5 = - 5 a

9 x^{2} + 6 x + 5

x^{2} - 15 = 2 x

0 = 6 x^{2} - 8

y, x^{2} y^{2} + 3 x y = 1

What are the solutions to the equation x^2+18x+27=8x+3 ?
The solutions to the equation x^2+18x+27=8x+3 are x=-4,x=-6
Find the zeros of x^2+18x+27=8x+3
The zeros of x^2+18x+27=8x+3 are x=-4,x=-6