What are the solutions to the equation 4x^2+44x+96=0 ?

The solutions to the equation 4x^2+44x+96=0 are x=-3,x=-8

Find the zeros of 4x^2+44x+96=0

The zeros of 4x^2+44x+96=0 are x=-3,x=-8

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4 x^{2} + 44 x + 96 = 0

x = - 3, x = - 8

Solution steps

4 x^{2} + 44 x + 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 44 \pm 4 4 ^{2} - 4 \cdot 4 \cdot 96}{2 \cdot 4}

4 4^{2} - 4 \cdot 4 \cdot 96 = 20

x_{1, 2} = \frac{- 44 \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 44 + 20}{2 \cdot 4}, x_{2} = \frac{- 44 - 20}{2 \cdot 4}

x = \frac{- 44 + 20}{2 \cdot 4} : - 3

x = \frac{- 44 - 20}{2 \cdot 4} : - 8

The solutions to the quadratic equation are:

x = - 3, x = - 8

- 0.3 x^{2} - 3.5 x + 20 = 0

- y^{2} - 2 y

3 a^{2} + 8 a + 5 = 0

6750000 = 100 x - 0.0001 x^{2}

x, 10 0^{2} + 13 0^{2} = x^{2}

What are the solutions to the equation 4x^2+44x+96=0 ?
The solutions to the equation 4x^2+44x+96=0 are x=-3,x=-8
Find the zeros of 4x^2+44x+96=0
The zeros of 4x^2+44x+96=0 are x=-3,x=-8