What are the solutions to the equation roots r^2+16 ?

The solutions to the equation roots r^2+16 are r=4i,r=-4i

Find the zeros of roots r^2+16

The zeros of roots r^2+16 are r=4i,r=-4i

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roots

r^{2} + 16

r = 4 i, r = - 4 i

Solution steps

r^{2} + 16

The roots are the intercepts with the x-axis

(y = 0)

r^{2} + 16 = 0

Move

16

to the right side

r^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 16, r = - - 16

- 16 = 4 i

- - 16 = - 4 i

r = 4 i, r = - 4 i

0.513 x \frac{0.05}{4} = x^{2}

r^{2} + 2 r + 64 = 0

6 x^{2} + 22 x = 8

16 (9 - 2 x)^{2} = 36

4 x^{2} + 4 x + 2 x - 4 = 0

What are the solutions to the equation roots r^2+16 ?
The solutions to the equation roots r^2+16 are r=4i,r=-4i
Find the zeros of roots r^2+16
The zeros of roots r^2+16 are r=4i,r=-4i