What are the solutions to the equation x=-x^2+1000x ?

The solutions to the equation x=-x^2+1000x are x=0,x=999

Find the zeros of x=-x^2+1000x

The zeros of x=-x^2+1000x are x=0,x=999

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x = - x^{2} + 1000 x

x = 0, x = 999

Solution steps

x = - x^{2} + 1000 x

Switch sides

- x^{2} + 1000 x = x

Move

x

to the left side

- x^{2} + 999 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 999 \pm 99 9 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

99 9^{2} - 4 (- 1) \cdot 0 = 999

x_{1, 2} = \frac{- 999 \pm 999}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 999 + 999}{2 ( - 1 )}, x_{2} = \frac{- 999 - 999}{2 ( - 1 )}

x = \frac{- 999 + 999}{2 ( - 1 )} : 0

x = \frac{- 999 - 999}{2 ( - 1 )} : 999

The solutions to the quadratic equation are:

x = 0, x = 999

- x^{2} + 3 x + a = 0

0 = 12 x^{2} - 24 x - 40

- 6 x^{2} + 72 x - 192 = 0

2 x^{2} - 16 x + 31

x^{2} + 18 x + 17 = 0

What are the solutions to the equation x=-x^2+1000x ?
The solutions to the equation x=-x^2+1000x are x=0,x=999
Find the zeros of x=-x^2+1000x
The zeros of x=-x^2+1000x are x=0,x=999