What are the solutions to the equation r^2-3r-28=0 ?

The solutions to the equation r^2-3r-28=0 are r=7,r=-4

Find the zeros of r^2-3r-28=0

The zeros of r^2-3r-28=0 are r=7,r=-4

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r^{2} - 3 r - 28 = 0

r = 7, r = - 4

Solution steps

r^{2} - 3 r - 28 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 28) = 11

r_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 1}, r_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 1}

r = \frac{- ( - 3 ) + 11}{2 \cdot 1} : 7

r = \frac{- ( - 3 ) - 11}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

r = 7, r = - 4

2 x^{2} - 9 x = - 10

8 x - 3 = - 3 x^{2}

- 6 (x + 5)^{2} + 54 = 0

x^{2} + 11 x + 24 = 0

2 x^{2} + 16 x + 7

What are the solutions to the equation r^2-3r-28=0 ?
The solutions to the equation r^2-3r-28=0 are r=7,r=-4
Find the zeros of r^2-3r-28=0
The zeros of r^2-3r-28=0 are r=7,r=-4