What are the solutions to the equation (-2x+7)(x-1)=3 ?

The solutions to the equation (-2x+7)(x-1)=3 are x=2,x= 5/2

Find the zeros of (-2x+7)(x-1)=3

The zeros of (-2x+7)(x-1)=3 are x=2,x= 5/2

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(- 2 x + 7) (x - 1) = 3

x = 2, x = \frac{5}{2}

Decimal Notation

x = 2, x = 2.5

Solution steps

(- 2 x + 7) (x - 1) = 3

Expand

(- 2 x + 7) (x - 1) : - 2 x^{2} + 9 x - 7

- 2 x^{2} + 9 x - 7 = 3

Move

3

to the left side

- 2 x^{2} + 9 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 2 ) ( - 10 )}{2 ( - 2 )}

9^{2} - 4 (- 2) (- 10) = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 ( - 2 )}, x_{2} = \frac{- 9 - 1}{2 ( - 2 )}

x = \frac{- 9 + 1}{2 ( - 2 )} : 2

x = \frac{- 9 - 1}{2 ( - 2 )} : \frac{5}{2}

The solutions to the quadratic equation are:

x = 2, x = \frac{5}{2}

n^{2} + 3 n = 10

s, (s + 4)^{2} + 9 = 0

3 x^{2} + 4 x + 9 = 8

0 = - \frac{25}{36} x^{2} + 16 \frac{2}{3} x

x^{2} - 16 x + 13 = - 10 x

What are the solutions to the equation (-2x+7)(x-1)=3 ?
The solutions to the equation (-2x+7)(x-1)=3 are x=2,x= 5/2
Find the zeros of (-2x+7)(x-1)=3
The zeros of (-2x+7)(x-1)=3 are x=2,x= 5/2