What are the solutions to the equation solvefor y,(x-1)^2+y^2=0 ?

The solutions to the equation solvefor y,(x-1)^2+y^2=0 are y=sqrt(-x^2+2x-1),y=-sqrt(-x^2+2x-1)

Find the zeros of solvefor y,(x-1)^2+y^2=0

The zeros of solvefor y,(x-1)^2+y^2=0 are y=sqrt(-x^2+2x-1),y=-sqrt(-x^2+2x-1)

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solve for

y, (x - 1)^{2} + y^{2} = 0

y = - x^{2} + 2 x - 1, y = - - x^{2} + 2 x - 1

Solution steps

(x - 1)^{2} + y^{2} = 0

Move

(x - 1)^{2}

to the right side

y^{2} = - (x - 1)^{2}

Simplify

- (x - 1)^{2} : - x^{2} + 2 x - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - x^{2} + 2 x - 1, y = - - x^{2} + 2 x - 1

x^{2} + 16 x + 71

x^{2} - 109 = - 8 x

x^{2} = 1 2^{2} + 6^{2}

- 16 x^{2} + 73 x + 6 = 0

- 4 q^{2} + 68 q = 8

What are the solutions to the equation solvefor y,(x-1)^2+y^2=0 ?
The solutions to the equation solvefor y,(x-1)^2+y^2=0 are y=sqrt(-x^2+2x-1),y=-sqrt(-x^2+2x-1)
Find the zeros of solvefor y,(x-1)^2+y^2=0
The zeros of solvefor y,(x-1)^2+y^2=0 are y=sqrt(-x^2+2x-1),y=-sqrt(-x^2+2x-1)