What is the answer to (2x)/(2x+3)-(2x)/(2x-3)=1 ?

The answer to (2x)/(2x+3)-(2x)/(2x-3)=1 is x=(3(sqrt(2)-1))/2 ,x=-(3(1+sqrt(2)))/2

Solve for x: (2x)/(2x+3)-(2x)/(2x-3)=1

The solution is x=(3(sqrt(2)-1))/2 ,x=-(3(1+sqrt(2)))/2

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\frac{2 x}{2 x + 3} - \frac{2 x}{2 x - 3} = 1

x = \frac{3 ( 2 - 1 )}{2}, x = - \frac{3 ( 1 + 2 )}{2}

Decimal Notation

x = 0.62132 \dots, x = - 3.62132 \dots

Solution steps

\frac{2 x}{2 x + 3} - \frac{2 x}{2 x - 3} = 1

Multiply by LCM

2 x (2 x - 3) - 2 x (2 x + 3) = (2 x + 3) (2 x - 3)

Solve

2 x (2 x - 3) - 2 x (2 x + 3) = (2 x + 3) (2 x - 3) : x = \frac{3 ( 2 - 1 )}{2}, x = - \frac{3 ( 1 + 2 )}{2}

x = \frac{3 ( 2 - 1 )}{2}, x = - \frac{3 ( 1 + 2 )}{2}

Verify Solutions

Find undefined (singularity) points:

x = - \frac{3}{2}, x = \frac{3}{2}

Combine undefined points with solutions:

x = \frac{3 ( 2 - 1 )}{2}, x = - \frac{3 ( 1 + 2 )}{2}

\frac{2}{3 x} + \frac{1}{6} = \frac{4}{3 x}

\frac{x}{x - 1} = 1 - \frac{1}{1 - x}

\frac{10}{2} = \frac{5}{x}

\frac{4}{5} + \frac{3}{4 x} = - \frac{1}{6 x}

\frac{3}{x + 2} - \frac{1}{x} = \frac{1}{5 x}

What is the answer to (2x)/(2x+3)-(2x)/(2x-3)=1 ?
The answer to (2x)/(2x+3)-(2x)/(2x-3)=1 is x=(3(sqrt(2)-1))/2 ,x=-(3(1+sqrt(2)))/2
Solve for x: (2x)/(2x+3)-(2x)/(2x-3)=1
The solution is x=(3(sqrt(2)-1))/2 ,x=-(3(1+sqrt(2)))/2