What is the answer to x-1=(x^2-4x+3)/(x+2) ?

The answer to x-1=(x^2-4x+3)/(x+2) is x=1

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x-1=(x^2-4x+3)/(x+2)

x - 1 = \frac{x ^{2} - 4 x + 3}{x + 2}

x = 1

Solution steps

x - 1 = \frac{x ^{2} - 4 x + 3}{x + 2}

Multiply both sides by

x + 2

x (x + 2) - (x + 2) = x^{2} - 4 x + 3

Expand

x (x + 2) - (x + 2) : x^{2} + x - 2

x^{2} + x - 2 = x^{2} - 4 x + 3

Move

2

to the right side

x^{2} + x = x^{2} - 4 x + 5

Subtract

x^{2} - 4 x

from both sides

x^{2} + x - (x^{2} - 4 x) = x^{2} - 4 x + 5 - (x^{2} - 4 x)

Simplify

5 x = 5

Divide both sides by

5

x = 1

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = 1

\frac{x ^{2} - 10}{x - 1} = \frac{- 14 - 5 x}{x - 1}

\frac{1}{x ^{2} - 2 x - 7} = 1

1 + \frac{x ^{2} - 5 x - 24}{3 x} = \frac{x - 6}{3 x}

\frac{4}{x - 3} + \frac{x}{2} = - 2

\frac{7}{x} = \frac{21}{9}

What is the answer to x-1=(x^2-4x+3)/(x+2) ?
The answer to x-1=(x^2-4x+3)/(x+2) is x=1
Solve for x: x-1=(x^2-4x+3)/(x+2)
The solution is x=1