What is the answer to (4x+1)/(x+1)-3=(12)/(x^2-1) ?

The answer to (4x+1)/(x+1)-3=(12)/(x^2-1) is x=5,x=-2

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(4x+1)/(x+1)-3=(12)/(x^2-1)

\frac{4 x + 1}{x + 1} - 3 = \frac{12}{x ^{2} - 1}

x = 5, x = - 2

Solution steps

\frac{4 x + 1}{x + 1} - 3 = \frac{12}{x ^{2} - 1}

Multiply by LCM

(4 x + 1) (x - 1) - 3 (x + 1) (x - 1) = 12

Solve

(4 x + 1) (x - 1) - 3 (x + 1) (x - 1) = 12 : x = 5, x = - 2

x = 5, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 1

Combine undefined points with solutions:

x = 5, x = - 2

\frac{3 x}{x + 1} = \frac{12}{x ^{2} - 1} + 2

\frac{x - 3}{x + 5} = \frac{x}{x + 2}

\frac{x ^{3}}{x + x + x} = 12

x + \frac{4}{x} = - 5

y, x = \frac{1}{y + 2}

What is the answer to (4x+1)/(x+1)-3=(12)/(x^2-1) ?
The answer to (4x+1)/(x+1)-3=(12)/(x^2-1) is x=5,x=-2
Solve for x: (4x+1)/(x+1)-3=(12)/(x^2-1)
The solution is x=5,x=-2