What is the answer to (x-3)/(x^2-9)+(x+1)/(x+3)=x+2 ?

The answer to (x-3)/(x^2-9)+(x+1)/(x+3)=x+2 is x=-2

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(x-3)/(x^2-9)+(x+1)/(x+3)=x+2

\frac{x - 3}{x ^{2} - 9} + \frac{x + 1}{x + 3} = x + 2

x = - 2

Solution steps

\frac{x - 3}{x ^{2} - 9} + \frac{x + 1}{x + 3} = x + 2

Simplify

\frac{x - 3}{x ^{2} - 9} : \frac{1}{x + 3}

\frac{1}{x + 3} + \frac{x + 1}{x + 3} = x + 2

Multiply both sides by

x + 3

x + 2 = x (x + 3) + 2 (x + 3)

Solve

x + 2 = x (x + 3) + 2 (x + 3) : x = - 2

x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 3, x = - 3

Combine undefined points with solutions:

x = - 2

\frac{2}{x} = \frac{4}{10}

\frac{1}{x} - \frac{2}{x - 3} = 4

y, y - \frac{1}{x} = 11

\frac{12}{x + 5} = - \frac{12}{5}

x - \frac{12}{x} = - 4

What is the answer to (x-3)/(x^2-9)+(x+1)/(x+3)=x+2 ?
The answer to (x-3)/(x^2-9)+(x+1)/(x+3)=x+2 is x=-2
Solve for x: (x-3)/(x^2-9)+(x+1)/(x+3)=x+2
The solution is x=-2