What is the answer to (x^2)/(x-3)=(x+2)/(2x-5) ?

The answer to (x^2)/(x-3)=(x+2)/(2x-5) is x=2,x=(1+sqrt(7))/2 ,x=(1-sqrt(7))/2

Solve for x: (x^2)/(x-3)=(x+2)/(2x-5)

The solution is x=2,x=(1+sqrt(7))/2 ,x=(1-sqrt(7))/2

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\frac{x ^{2}}{x - 3} = \frac{x + 2}{2 x - 5}

x = 2, x = \frac{1 + 7}{2}, x = \frac{1 - 7}{2}

Decimal Notation

x = 2, x = 1.82287 \dots, x = - 0.82287 \dots

Solution steps

\frac{x ^{2}}{x - 3} = \frac{x + 2}{2 x - 5}

Cross multiply

x^{2} (2 x - 5) = (x - 3) (x + 2)

Solve

x^{2} (2 x - 5) = (x - 3) (x + 2) : x = 2, x = \frac{1 + 7}{2}, x = \frac{1 - 7}{2}

x = 2, x = \frac{1 + 7}{2}, x = \frac{1 - 7}{2}

Verify Solutions

Find undefined (singularity) points:

x = 3, x = \frac{5}{2}

Combine undefined points with solutions:

x = 2, x = \frac{1 + 7}{2}, x = \frac{1 - 7}{2}

\frac{1}{x} + \frac{1}{x + 1} = \frac{7}{12}

\frac{2}{x - 5} = \frac{2 x}{3}

- 9 + \frac{1}{x + 9} = - \frac{x}{x + 9}

\frac{1}{x - 1} + 7 = \frac{x}{x - 1}

x + \frac{5}{x} = - 6

What is the answer to (x^2)/(x-3)=(x+2)/(2x-5) ?
The answer to (x^2)/(x-3)=(x+2)/(2x-5) is x=2,x=(1+sqrt(7))/2 ,x=(1-sqrt(7))/2
Solve for x: (x^2)/(x-3)=(x+2)/(2x-5)
The solution is x=2,x=(1+sqrt(7))/2 ,x=(1-sqrt(7))/2