What is the answer to 2/(x^2-x)= 1/(x-1) ?

The answer to 2/(x^2-x)= 1/(x-1) is x=2

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2/(x^2-x)= 1/(x-1)

\frac{2}{x ^{2} - x} = \frac{1}{x - 1}

x = 2

Solution steps

\frac{2}{x ^{2} - x} = \frac{1}{x - 1}

Cross multiply

2 (x - 1) = x^{2} - x

Solve

2 (x - 1) = x^{2} - x : x = 2, x = 1

x = 2, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 0, x = 1

Since the equation is undefined for:

1

x = 2

\frac{1}{x} = \frac{1}{5 x} - \frac{x - 1}{5 x}

- \frac{4}{x ^{2}} + \frac{1}{2} = 0

\frac{1}{x} + \frac{1}{x + 3} = \frac{1}{2}

x - \frac{x + 3}{x - 3} = \frac{2}{x - 3}

x + \frac{11}{x} = - 12

What is the answer to 2/(x^2-x)= 1/(x-1) ?
The answer to 2/(x^2-x)= 1/(x-1) is x=2
Solve for x: 2/(x^2-x)= 1/(x-1)
The solution is x=2