What is the answer to (2x-3)/(x+1)=(x+6)/(x-2) ?

The answer to (2x-3)/(x+1)=(x+6)/(x-2) is x=14,x=0

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(2x-3)/(x+1)=(x+6)/(x-2)

\frac{2 x - 3}{x + 1} = \frac{x + 6}{x - 2}

x = 14, x = 0

Solution steps

\frac{2 x - 3}{x + 1} = \frac{x + 6}{x - 2}

Cross multiply

(2 x - 3) (x - 2) = (x + 1) (x + 6)

Solve

(2 x - 3) (x - 2) = (x + 1) (x + 6) : x = 14, x = 0

x = 14, x = 0

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 2

Combine undefined points with solutions:

x = 14, x = 0

\frac{6 x - 1}{x + 5} - \frac{1}{6 x} = 6

\frac{1}{y - 2} = \frac{2 y + 1}{y ^{2} - 4}

\frac{15 - 2 x - x ^{2}}{x - 4} = 0

\frac{3 z - 6}{7 - 2 z} = \frac{1.2}{3.2}

\frac{x}{x - 6} - 8 = - \frac{1}{x - 6}

What is the answer to (2x-3)/(x+1)=(x+6)/(x-2) ?
The answer to (2x-3)/(x+1)=(x+6)/(x-2) is x=14,x=0
Solve for x: (2x-3)/(x+1)=(x+6)/(x-2)
The solution is x=14,x=0