What is the answer to 1+x/(x+1)= 1/(x^2+x) ?

The answer to 1+x/(x+1)= 1/(x^2+x) is x= 1/2

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1+x/(x+1)= 1/(x^2+x)

1 + \frac{x}{x + 1} = \frac{1}{x ^{2} + x}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

1 + \frac{x}{x + 1} = \frac{1}{x ^{2} + x}

Multiply by LCM

x (x + 1) + x^{2} = 1

Solve

x (x + 1) + x^{2} = 1 : x = \frac{1}{2}, x = - 1

x = \frac{1}{2}, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0

Since the equation is undefined for:

- 1

x = \frac{1}{2}

\frac{9 x}{x - 1} - 1 = \frac{9}{x ^{2} - x}

\frac{x}{x + 2} = \frac{10}{15}

1 - \frac{2 x - 3}{x + 5} = \frac{x - 2}{10}

t, v = \frac{d}{t}

\frac{2}{x + 2} + \frac{3}{x} = \frac{- x}{x + 2}

What is the answer to 1+x/(x+1)= 1/(x^2+x) ?
The answer to 1+x/(x+1)= 1/(x^2+x) is x= 1/2
Solve for x: 1+x/(x+1)= 1/(x^2+x)
The solution is x= 1/2