What is the answer to 1+2/(x-4)= 7/(x^2-16) ?

The answer to 1+2/(x-4)= 7/(x^2-16) is x=3,x=-5

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1+2/(x-4)= 7/(x^2-16)

1 + \frac{2}{x - 4} = \frac{7}{x ^{2} - 16}

x = 3, x = - 5

Solution steps

1 + \frac{2}{x - 4} = \frac{7}{x ^{2} - 16}

Multiply by LCM

(x - 4) (x + 4) + 2 (x + 4) = 7

Solve

(x - 4) (x + 4) + 2 (x + 4) = 7 : x = 3, x = - 5

x = 3, x = - 5

Verify Solutions

Find undefined (singularity) points:

x = 4, x = - 4

Combine undefined points with solutions:

x = 3, x = - 5

\frac{10}{y + 11} = \frac{25}{- 3 y}

- 1 - \frac{4}{x} = - 5 x

\frac{2 x}{x + 2} = \frac{3 x}{x + 5} - 1

y, \frac{2}{x} - \frac{1}{y} = 4

- \frac{2}{x ^{2}} + \frac{1}{x} + 3 = 0

What is the answer to 1+2/(x-4)= 7/(x^2-16) ?
The answer to 1+2/(x-4)= 7/(x^2-16) is x=3,x=-5
Solve for x: 1+2/(x-4)= 7/(x^2-16)
The solution is x=3,x=-5