What is the answer to 1/(x+1)+2/(x^2-1)=1 ?

The answer to 1/(x+1)+2/(x^2-1)=1 is x=2

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1/(x+1)+2/(x^2-1)=1

\frac{1}{x + 1} + \frac{2}{x ^{2} - 1} = 1

x = 2

Solution steps

\frac{1}{x + 1} + \frac{2}{x ^{2} - 1} = 1

Multiply by LCM

x + 1 = (x + 1) (x - 1)

Solve

x + 1 = (x + 1) (x - 1) : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 1

Since the equation is undefined for:

- 1

x = 2

\frac{4}{x - 1} + \frac{3}{x} = 3

2 x - \frac{18}{x} = 0

\frac{4}{4 - x} = \frac{5}{4 + x}

\frac{x - 2}{x + 3} - 1 = \frac{3}{x + 2}

x - \frac{12}{x} = - 1

What is the answer to 1/(x+1)+2/(x^2-1)=1 ?
The answer to 1/(x+1)+2/(x^2-1)=1 is x=2
Solve for x: 1/(x+1)+2/(x^2-1)=1
The solution is x=2