What is the answer to |x^2-8x|=16 ?

The answer to |x^2-8x|=16 is x=4(1-sqrt(2))\lor x=4\lor x=4(1+sqrt(2))

Solve for x: |x^2-8x|=16

The solution is x=4(1-sqrt(2))\lor x=4\lor x=4(1+sqrt(2))

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x^{2} - 8 x = 16

x = 4 (1 - 2) or x = 4 or x = 4 (1 + 2)

Decimal Notation

x = - 1.65685 \dots, x = 4, x = 9.65685 \dots

Solution steps

x^{2} - 8 x = 16

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 8 x = - 16 or x^{2} - 8 x = 16

x^{2} - 8 x = - 16 or x^{2} - 8 x = 16

x = 4 or (x = 4 (1 - 2) or x = 4 (1 + 2))

x = 4 (1 - 2) or x = 4 or x = 4 (1 + 2)

4 x + 1 = 2 x + 3

2 x^{3} - 16

4 q^{2} - 4 q - 80

1 2^{\frac{1}{2}}

\frac{5}{12} + \frac{1}{3}

What is the answer to |x^2-8x|=16 ?
The answer to |x^2-8x|=16 is x=4(1-sqrt(2))\lor x=4\lor x=4(1+sqrt(2))
Solve for x: |x^2-8x|=16
The solution is x=4(1-sqrt(2))\lor x=4\lor x=4(1+sqrt(2))