What is the answer to x^{-2}-3x^{-1}-4=0 ?

The answer to x^{-2}-3x^{-1}-4=0 is x=-1,x= 1/4

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x^{-2}-3x^{-1}-4=0

x^{- 2} - 3 x^{- 1} - 4 = 0

x = - 1, x = \frac{1}{4}

Decimal Notation

x = - 1, x = 0.25

Solution steps

x^{- 2} - 3 x^{- 1} - 4 = 0

Refine

\frac{1}{x ^{2}} - \frac{3}{x} - 4 = 0

Multiply by LCM

1 - 3 x - 4 x^{2} = 0

Solve

1 - 3 x - 4 x^{2} = 0 : x = - 1, x = \frac{1}{4}

x = - 1, x = \frac{1}{4}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 1, x = \frac{1}{4}

a, \frac{n}{q} = \frac{b}{a}

\frac{x}{x - 2} - \frac{x - 2}{x} = \frac{5}{2}

\frac{1}{x + 7} + \frac{1}{x - 3} = 0

\frac{6}{x - 14} = \frac{8}{2}

- \frac{7}{x - 1} + 4 x = - \frac{7 x}{x - 1}

What is the answer to x^{-2}-3x^{-1}-4=0 ?
The answer to x^{-2}-3x^{-1}-4=0 is x=-1,x= 1/4
Solve for x: x^{-2}-3x^{-1}-4=0
The solution is x=-1,x= 1/4