What is the answer to 1/(x+4)+8/(x^2-16)=1 ?

The answer to 1/(x+4)+8/(x^2-16)=1 is x=5

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1/(x+4)+8/(x^2-16)=1

\frac{1}{x + 4} + \frac{8}{x ^{2} - 16} = 1

x = 5

Solution steps

\frac{1}{x + 4} + \frac{8}{x ^{2} - 16} = 1

Multiply by LCM

x + 4 = (x + 4) (x - 4)

Solve

x + 4 = (x + 4) (x - 4) : x = 5, x = - 4

x = 5, x = - 4

Verify Solutions

Find undefined (singularity) points:

x = - 4, x = 4

Since the equation is undefined for:

- 4

x = 5

x + \frac{2 x + 3}{x - 1} = \frac{5}{x - 1}

\frac{x ^{2} - 4 x}{x - 2} = 1 + \frac{4}{2 - x}

x, \frac{1}{x} = \frac{1}{y} + \frac{1}{n}

5 - \frac{1600}{x ^{2}} = 0

3 - \frac{x}{x + 3} = \frac{1}{x + 3}

What is the answer to 1/(x+4)+8/(x^2-16)=1 ?
The answer to 1/(x+4)+8/(x^2-16)=1 is x=5
Solve for x: 1/(x+4)+8/(x^2-16)=1
The solution is x=5