What is the answer to 1-x^{-2}=0 ?

The answer to 1-x^{-2}=0 is x=1,x=-1

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1-x^{-2}=0

1 - x^{- 2} = 0

x = 1, x = - 1

Solution steps

1 - x^{- 2} = 0

Refine

1 - \frac{1}{x ^{2}} = 0

Multiply both sides by

x^{2}

x^{2} - 1 = 0

Solve

x^{2} - 1 = 0 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1, x = - 1

\frac{2}{x + 1} + \frac{1}{x + 1} = 3

f, T = \frac{1}{f}

\frac{1}{x - 3} = \frac{x + 2}{7 x + 14}

\frac{8}{3 x - 2} = \frac{2}{x - 1}

\frac{5}{x + 5} - 9 = \frac{x}{x + 5}