What are the solutions to the equation (x+2)^2-32=0 ?

The solutions to the equation (x+2)^2-32=0 are x=4sqrt(2)-2,x=-4sqrt(2)-2

Find the zeros of (x+2)^2-32=0

The zeros of (x+2)^2-32=0 are x=4sqrt(2)-2,x=-4sqrt(2)-2

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(x + 2)^{2} - 32 = 0

x = 42 - 2, x = - 42 - 2

Decimal Notation

x = 3.65685 \dots, x = - 7.65685 \dots

Solution steps

(x + 2)^{2} - 32 = 0

Move

32

to the right side

(x + 2)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 32 : x = 42 - 2

Solve

x + 2 = - 32 : x = - 42 - 2

The solutions to the quadratic equation are:

x = 42 - 2, x = - 42 - 2

458

- 4 (\frac{1}{2})

7 x^{2} + 17 x + 6

3 + 4 i \cdot 2 - 1 i

x^{3} + 10 x^{2} + 19 x - 30

What are the solutions to the equation (x+2)^2-32=0 ?
The solutions to the equation (x+2)^2-32=0 are x=4sqrt(2)-2,x=-4sqrt(2)-2
Find the zeros of (x+2)^2-32=0
The zeros of (x+2)^2-32=0 are x=4sqrt(2)-2,x=-4sqrt(2)-2