What is the answer to 1/(x+1)-1/(x+2)= 1/2 ?

The answer to 1/(x+1)-1/(x+2)= 1/2 is x=0,x=-3

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1/(x+1)-1/(x+2)= 1/2

\frac{1}{x + 1} - \frac{1}{x + 2} = \frac{1}{2}

x = 0, x = - 3

Solution steps

\frac{1}{x + 1} - \frac{1}{x + 2} = \frac{1}{2}

Multiply by LCM

2 (x + 2) - 2 (x + 1) = (x + 1) (x + 2)

Solve

2 (x + 2) - 2 (x + 1) = (x + 1) (x + 2) : x = 0, x = - 3

x = 0, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = - 2

Combine undefined points with solutions:

x = 0, x = - 3

\frac{1}{x} = \frac{2}{x} + 1 + \frac{1}{1 - x}

1 - \frac{3}{x} = - \frac{x}{x + 2}

x - \frac{7}{x + 8} = 2 x

- 3 - \frac{x}{x + 8} = \frac{8}{x + 8}

6 - \frac{2}{x ^{2}} = 0

What is the answer to 1/(x+1)-1/(x+2)= 1/2 ?
The answer to 1/(x+1)-1/(x+2)= 1/2 is x=0,x=-3
Solve for x: 1/(x+1)-1/(x+2)= 1/2
The solution is x=0,x=-3