What is the answer to (3x^2-2)/(x^2+x+1)=2 ?

The answer to (3x^2-2)/(x^2+x+1)=2 is x=1-sqrt(5),x=1+sqrt(5)

Solve for x: (3x^2-2)/(x^2+x+1)=2

The solution is x=1-sqrt(5),x=1+sqrt(5)

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\frac{3 x ^{2} - 2}{x ^{2} + x + 1} = 2

x = 1 - 5, x = 1 + 5

Decimal Notation

x = - 1.23606 \dots, x = 3.23606 \dots

Solution steps

\frac{3 x ^{2} - 2}{x ^{2} + x + 1} = 2

Multiply both sides by

x^{2} + x + 1

3 x^{2} - 2 = 2 (x^{2} + x + 1)

Solve

3 x^{2} - 2 = 2 (x^{2} + x + 1) : x = 1 - 5, x = 1 + 5

x = 1 - 5, x = 1 + 5

5 x + \frac{1}{x} = 6

\frac{1}{x} - \frac{1}{45} = \frac{1}{2 x - 3}

x - \frac{2}{x + 3} = 2 x

A, A^{2} X^{- 1} B A^{- 2} = A^{5} B A^{- 3}

- \frac{1}{x ^{2}} = - 1

What is the answer to (3x^2-2)/(x^2+x+1)=2 ?
The answer to (3x^2-2)/(x^2+x+1)=2 is x=1-sqrt(5),x=1+sqrt(5)
Solve for x: (3x^2-2)/(x^2+x+1)=2
The solution is x=1-sqrt(5),x=1+sqrt(5)