What is the answer to solvefor y,x=(y+1)/(y+2) ?

The answer to solvefor y,x=(y+1)/(y+2) is y=(1-2x)/(x-1);\quad x\ne 1

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solvefor y,x=(y+1)/(y+2)

solve for

y, x = \frac{y + 1}{y + 2}

y = \frac{1 - 2 x}{x - 1}; x \neq = 1

Solution steps

x = \frac{y + 1}{y + 2}

Multiply both sides by

y + 2

x (y + 2) = y + 1

Expand

x (y + 2) : y x + 2 x

y x + 2 x = y + 1

Move

2 x

to the right side

y x = y + 1 - 2 x

Move

y

to the left side

y x - y = 1 - 2 x

Factor

y x - y : y (x - 1)

y (x - 1) = 1 - 2 x

Divide both sides by

x - 1; x \neq = 1

y = \frac{1 - 2 x}{x - 1}; x \neq = 1

\frac{1}{3 - x} = \frac{x ^{2} - 9}{( x - 3 ) ^{2}}

5 - \frac{900}{x ^{2}} = 0

0 = - \frac{1}{x ^{2}} - \frac{1}{x}

\frac{x - 5}{3 x + 4} = \frac{x - 5}{2 x + 1}

T + \frac{a}{N}

What is the answer to solvefor y,x=(y+1)/(y+2) ?
The answer to solvefor y,x=(y+1)/(y+2) is y=(1-2x)/(x-1);\quad x\ne 1