What is the answer to x^2= 2/(x^2+1) ?

The answer to x^2= 2/(x^2+1) is x=1,x=-1,x=sqrt(2)i,x=-sqrt(2)i

Solve for x: x^2= 2/(x^2+1)

The solution is x=1,x=-1,x=sqrt(2)i,x=-sqrt(2)i

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x^{2} = \frac{2}{x ^{2} + 1}

x = 1, x = - 1, x = 2 i, x = - 2 i

Solution steps

x^{2} = \frac{2}{x ^{2} + 1}

Multiply both sides by

x^{2} + 1

x^{2} (x^{2} + 1) = 2

Solve

x^{2} (x^{2} + 1) = 2 : x = 1, x = - 1, x = 2 i, x = - 2 i

x = 1, x = - 1, x = 2 i, x = - 2 i

d, \frac{p}{d + b} = \frac{g}{d}

\frac{2 x}{x ^{2} + 9} = - 2

\frac{1}{x + 1} - \frac{2}{x - 1} = 3

\frac{2}{3 x} = \frac{1}{9}

- 6 - \frac{1}{x + 1} = \frac{x}{x + 1}

What is the answer to x^2= 2/(x^2+1) ?
The answer to x^2= 2/(x^2+1) is x=1,x=-1,x=sqrt(2)i,x=-sqrt(2)i
Solve for x: x^2= 2/(x^2+1)
The solution is x=1,x=-1,x=sqrt(2)i,x=-sqrt(2)i