What is the answer to 6-1/(x+9)= 9/(x^2+9x) ?

The answer to 6-1/(x+9)= 9/(x^2+9x) is x= 1/6

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6-1/(x+9)= 9/(x^2+9x)

6 - \frac{1}{x + 9} = \frac{9}{x ^{2} + 9 x}

x = \frac{1}{6}

Decimal Notation

x = 0.16666 \dots

Solution steps

6 - \frac{1}{x + 9} = \frac{9}{x ^{2} + 9 x}

Multiply by LCM

6 x (x + 9) - x = 9

Solve

6 x (x + 9) - x = 9 : x = \frac{1}{6}, x = - 9

x = \frac{1}{6}, x = - 9

Verify Solutions

Find undefined (singularity) points:

x = - 9, x = 0

Since the equation is undefined for:

- 9

x = \frac{1}{6}

\frac{1}{2 n} + \frac{6 n - 9}{3 n} = \frac{2}{n}

1 + \frac{x}{x + 9} = \frac{1}{x + 9}

- \frac{x}{∣ x ∣} = 0

- 2 (2) + b = \frac{- 24}{x - b}

x + \frac{3}{x + 1} = \frac{5}{x + 1}

What is the answer to 6-1/(x+9)= 9/(x^2+9x) ?
The answer to 6-1/(x+9)= 9/(x^2+9x) is x= 1/6
Solve for x: 6-1/(x+9)= 9/(x^2+9x)
The solution is x= 1/6