What is the answer to (2x)/(x^2-25)+(4-x)/(x-5)=0 ?

The answer to (2x)/(x^2-25)+(4-x)/(x-5)=0 is x=-4

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(2x)/(x^2-25)+(4-x)/(x-5)=0

\frac{2 x}{x ^{2} - 25} + \frac{4 - x}{x - 5} = 0

x = - 4

Solution steps

\frac{2 x}{x ^{2} - 25} + \frac{4 - x}{x - 5} = 0

Multiply by LCM

2 x + (4 - x) (x + 5) = 0

Solve

2 x + (4 - x) (x + 5) = 0 : x = - 4, x = 5

x = - 4, x = 5

Verify Solutions

Find undefined (singularity) points:

x = 5, x = - 5

Since the equation is undefined for:

5

x = - 4

\frac{x ^{2} - 2 x + 1}{x ^{3} + x ^{2} - 2 x} = 1

\frac{100 - x}{x - 91} = \frac{17}{1}

\frac{1}{x + 2} + \frac{1}{x} = 1

1 + \frac{3}{x + 2} = \frac{3}{x ^{2} + 9 x + 14}

\frac{6}{x ^{2}} - \frac{49}{x} = 17

What is the answer to (2x)/(x^2-25)+(4-x)/(x-5)=0 ?
The answer to (2x)/(x^2-25)+(4-x)/(x-5)=0 is x=-4
Solve for x: (2x)/(x^2-25)+(4-x)/(x-5)=0
The solution is x=-4