What is the answer to (x^2-2x+1)/(x^3+x^2-2x)=1 ?

The answer to (x^2-2x+1)/(x^3+x^2-2x)=1 is x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

Solve for x: (x^2-2x+1)/(x^3+x^2-2x)=1

The solution is x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

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\frac{x ^{2} - 2 x + 1}{x ^{3} + x ^{2} - 2 x} = 1

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

\frac{x ^{2} - 2 x + 1}{x ^{3} + x ^{2} - 2 x} = 1

Simplify

\frac{x ^{2} - 2 x + 1}{x ^{3} + x ^{2} - 2 x} : \frac{x - 1}{x ( x + 2 )}

\frac{x - 1}{x ( x + 2 )} = 1

Multiply both sides by

x (x + 2)

x - 1 = x (x + 2)

Solve

x - 1 = x (x + 2) : x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

\frac{100 - x}{x - 91} = \frac{17}{1}

\frac{1}{x + 2} + \frac{1}{x} = 1

1 + \frac{3}{x + 2} = \frac{3}{x ^{2} + 9 x + 14}

\frac{6}{x ^{2}} - \frac{49}{x} = 17

\frac{8 1 ^{3 x + 2}}{9 ^{- 3 x}} = 243

What is the answer to (x^2-2x+1)/(x^3+x^2-2x)=1 ?
The answer to (x^2-2x+1)/(x^3+x^2-2x)=1 is x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2
Solve for x: (x^2-2x+1)/(x^3+x^2-2x)=1
The solution is x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2