What is the answer to 1/(x+1)+(2x+3)/(x^2-1)=0 ?

The answer to 1/(x+1)+(2x+3)/(x^2-1)=0 is x=-2/3

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1/(x+1)+(2x+3)/(x^2-1)=0

\frac{1}{x + 1} + \frac{2 x + 3}{x ^{2} - 1} = 0

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

\frac{1}{x + 1} + \frac{2 x + 3}{x ^{2} - 1} = 0

Multiply by LCM

3 x + 2 = 0

Move

2

to the right side

3 x = - 2

Divide both sides by

3

x = - \frac{2}{3}

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 1

Combine undefined points with solutions:

x = - \frac{2}{3}

- \frac{9}{x ^{2} + 3 x} + \frac{x}{x + 3} = - 1

4 - \frac{8}{x + 1} = \frac{8 x}{x + 1}

\frac{12}{x} + \frac{3}{4} = \frac{3}{2}

\frac{14000}{y} + 1500 = \frac{14000}{y - 3}

\frac{3}{x} + \frac{1}{4} = \frac{8}{x}

What is the answer to 1/(x+1)+(2x+3)/(x^2-1)=0 ?
The answer to 1/(x+1)+(2x+3)/(x^2-1)=0 is x=-2/3
Solve for x: 1/(x+1)+(2x+3)/(x^2-1)=0
The solution is x=-2/3