What is the answer to 3= 6/(2x^2-x-4) ?

The answer to 3= 6/(2x^2-x-4) is x=2,x=-3/2

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3= 6/(2x^2-x-4)

3 = \frac{6}{2 x ^{2} - x - 4}

x = 2, x = - \frac{3}{2}

Decimal Notation

x = 2, x = - 1.5

Solution steps

3 = \frac{6}{2 x ^{2} - x - 4}

Multiply both sides by

2 x^{2} - x - 4

3 (2 x^{2} - x - 4) = 6

Solve

3 (2 x^{2} - x - 4) = 6 : x = 2, x = - \frac{3}{2}

x = 2, x = - \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = \frac{1 + 33}{4}, x = \frac{1 - 33}{4}

Combine undefined points with solutions:

x = 2, x = - \frac{3}{2}

\frac{6}{y - 3} - \frac{6}{y} = - \frac{9}{y}

3 x - \frac{2}{x + 1} = 2 x

- \frac{2}{x} = 0

\frac{6}{y - 3} - \frac{6}{y} = \frac{- 9}{y}

\frac{3 x + 1}{5 x + 7} = \frac{6 x + 11}{10 x - 3}

What is the answer to 3= 6/(2x^2-x-4) ?
The answer to 3= 6/(2x^2-x-4) is x=2,x=-3/2
Solve for x: 3= 6/(2x^2-x-4)
The solution is x=2,x=-3/2