What is the answer to 1/((x+1))-1/((x-1))=1 ?

The answer to 1/((x+1))-1/((x-1))=1 is x=i,x=-i

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1/((x+1))-1/((x-1))=1

\frac{1}{( x + 1 )} - \frac{1}{( x - 1 )} = 1

x = i, x = - i

Solution steps

\frac{1}{( x + 1 )} - \frac{1}{( x - 1 )} = 1

Multiply by LCM

x - 1 - (x + 1) = (x + 1) (x - 1)

Solve

x - 1 - (x + 1) = (x + 1) (x - 1) : x = i, x = - i

x = i, x = - i

\frac{1}{x + 10} + \frac{20}{x ^{2} - 100} = 1

\frac{2 x + 17}{x + 1} = x + 5

\frac{1}{x + 3} - \frac{1}{x} = 5

- 7 - \frac{3}{x} = - 6 x

\frac{x ^{2} + x + 4}{2 x + 1} = \frac{4}{x}

What is the answer to 1/((x+1))-1/((x-1))=1 ?
The answer to 1/((x+1))-1/((x-1))=1 is x=i,x=-i
Solve for x: 1/((x+1))-1/((x-1))=1
The solution is x=i,x=-i