What is the answer to roots (x^2+ax+3x+a+2)/(x+1) ?

The answer to roots (x^2+ax+3x+a+2)/(x+1) is x=-a-2

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roots (x^2+ax+3x+a+2)/(x+1)

roots

\frac{x ^{2} + a x + 3 x + a + 2}{x + 1}

x = - a - 2

Solution steps

\frac{x ^{2} + a x + 3 x + a + 2}{x + 1}

The roots are the intercepts with the x-axis

(y = 0)

\frac{x ^{2} + a x + 3 x + a + 2}{x + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + a x + 3 x + a + 2 = 0

Solve

x^{2} + a x + 3 x + a + 2 = 0 : x = - 1, x = - a - 2

x = - 1, x = - a - 2

Verify Solutions

Find undefined (singularity) points:

x = - 1

Since the equation is undefined for:

- 1

x = - a - 2

- \frac{54}{w} = 6

\frac{1}{2 x} + \frac{3}{x + 7} = - \frac{1}{x}

2 x + \frac{5}{x - 5} = \frac{x}{x - 5}

4 π x - \frac{4000}{x ^{2}} = 0

\frac{4 x + 1}{x + 1} = \frac{12}{x ^{2} - 1} + 3

What is the answer to roots (x^2+ax+3x+a+2)/(x+1) ?
The answer to roots (x^2+ax+3x+a+2)/(x+1) is x=-a-2