What is the answer to 1/(x^2)+1/x-12=0 ?

The answer to 1/(x^2)+1/x-12=0 is x=-1/4 ,x= 1/3

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1/(x^2)+1/x-12=0

\frac{1}{x ^{2}} + \frac{1}{x} - 12 = 0

x = - \frac{1}{4}, x = \frac{1}{3}

Decimal Notation

x = - 0.25, x = 0.33333 \dots

Solution steps

\frac{1}{x ^{2}} + \frac{1}{x} - 12 = 0

Multiply by LCM

1 + x - 12 x^{2} = 0

Solve

1 + x - 12 x^{2} = 0 : x = - \frac{1}{4}, x = \frac{1}{3}

x = - \frac{1}{4}, x = \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{1}{4}, x = \frac{1}{3}

\frac{10 x - 1 + 6}{12 x} = 10

\frac{1}{x - 4} + 2 = \frac{4}{x ^{2} - 4 x}

1 - \frac{2}{x - 1} = \frac{2}{x ^{2} - 3 x + 2}

4 + \frac{1}{x} - \frac{1}{x ^{2}} = 0

- 2 + \frac{x}{x + 2} = - \frac{7}{x + 2}

What is the answer to 1/(x^2)+1/x-12=0 ?
The answer to 1/(x^2)+1/x-12=0 is x=-1/4 ,x= 1/3
Solve for x: 1/(x^2)+1/x-12=0
The solution is x=-1/4 ,x= 1/3