What is the answer to solvefor f,f^{-1}(x)=(-2x+2)/(x+7) ?

The answer to solvefor f,f^{-1}(x)=(-2x+2)/(x+7) is f=(x(x+7))/(-2x+2);\quad x\ne-7,x\ne 1

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solvefor f,f^{-1}(x)=(-2x+2)/(x+7)

solve for

f, f^{- 1} (x) = \frac{- 2 x + 2}{x + 7}

f = \frac{x ( x + 7 )}{- 2 x + 2}; x \neq = - 7, x \neq = 1

Solution steps

f^{- 1} (x) = \frac{- 2 x + 2}{x + 7}

Refine

\frac{x}{f} = \frac{- 2 x + 2}{x + 7}

Cross multiply

x (x + 7) = f (- 2 x + 2)

Switch sides

f (- 2 x + 2) = x (x + 7)

Divide both sides by

- 2 x + 2; x \neq = 1

f = \frac{x ( x + 7 )}{- 2 x + 2}; x \neq = - 7, x \neq = 1

\frac{x - 7}{2 x - 9} = \frac{4}{3}

\frac{1}{x} + 2 = - \frac{5}{x ^{2} + 6 x}

\frac{2}{( x + 1 ) ^{3}} = 0

\frac{4 x - 1}{2 x + 3} = \frac{2 x + 1}{6 x + 5}

\frac{1}{x + 2} = \frac{x - 2}{5}

What is the answer to solvefor f,f^{-1}(x)=(-2x+2)/(x+7) ?
The answer to solvefor f,f^{-1}(x)=(-2x+2)/(x+7) is f=(x(x+7))/(-2x+2);\quad x\ne-7,x\ne 1