What is the answer to solvefor a, 1/a+1/b = 1/(a+b) ?

The answer to solvefor a, 1/a+1/b = 1/(a+b) is a=-b/2+i(sqrt(3)b)/2 ,a=-b/2-i(sqrt(3)b)/2

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solvefor a, 1/a+1/b = 1/(a+b)

solve for

a, \frac{1}{a} + \frac{1}{b} = \frac{1}{a + b}

a = - \frac{b}{2} + i \frac{3 b}{2}, a = - \frac{b}{2} - i \frac{3 b}{2}

Solution steps

\frac{1}{a} + \frac{1}{b} = \frac{1}{a + b}

Multiply by LCM

b (a + b) + a (a + b) = ab

Solve

b (a + b) + a (a + b) = ab : a = - \frac{b}{2} + i \frac{3 b}{2}, a = - \frac{b}{2} - i \frac{3 b}{2}

a = - \frac{b}{2} + i \frac{3 b}{2}, a = - \frac{b}{2} - i \frac{3 b}{2}

M, t = \frac{b}{4 - M ^{3}}

- 4 x + \frac{4}{x} = 0

\frac{2 x + 3}{2} - \frac{3 x}{x - 4} = x

x + \frac{x}{x - 2} = 0

\frac{12}{t} + t - 8 = 0

What is the answer to solvefor a, 1/a+1/b = 1/(a+b) ?
The answer to solvefor a, 1/a+1/b = 1/(a+b) is a=-b/2+i(sqrt(3)b)/2 ,a=-b/2-i(sqrt(3)b)/2