What is the answer to (2z+6)/(z+2)=3-1/z ?

The answer to (2z+6)/(z+2)=3-1/z is z=2,z=-1

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(2z+6)/(z+2)=3-1/z

\frac{2 z + 6}{z + 2} = 3 - \frac{1}{z}

z = 2, z = - 1

Solution steps

\frac{2 z + 6}{z + 2} = 3 - \frac{1}{z}

Multiply by LCM

z (2 z + 6) = 3 z (z + 2) - (z + 2)

Solve

z (2 z + 6) = 3 z (z + 2) - (z + 2) : z = 2, z = - 1

z = 2, z = - 1

Verify Solutions

Find undefined (singularity) points:

z = - 2, z = 0

Combine undefined points with solutions:

z = 2, z = - 1

\frac{2}{z} = 0.05

\frac{5}{3} - \frac{2}{x} = \frac{8}{x}

\frac{5}{2 x + 1} = \frac{3}{x + 3}

1 - \frac{6}{x ^{2}} = 0

- z + z^{- 2} = 2

What is the answer to (2z+6)/(z+2)=3-1/z ?
The answer to (2z+6)/(z+2)=3-1/z is z=2,z=-1
Solve for z: (2z+6)/(z+2)=3-1/z
The solution is z=2,z=-1