What is the answer to (2x^2-5)/(x+1)=x-1 ?

The answer to (2x^2-5)/(x+1)=x-1 is x=2,x=-2

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(2x^2-5)/(x+1)=x-1

\frac{2 x ^{2} - 5}{x + 1} = x - 1

x = 2, x = - 2

Solution steps

\frac{2 x ^{2} - 5}{x + 1} = x - 1

Multiply both sides by

x + 1

2 x^{2} - 5 = x (x + 1) - (x + 1)

Solve

2 x^{2} - 5 = x (x + 1) - (x + 1) : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = 2, x = - 2

\frac{x ^{2} + 9}{3 x ^{2}} = \frac{13}{12}

x = \frac{6}{2 x + 1}

\frac{3 x}{2} + \frac{5 - x}{x} = 4

\frac{1}{s + a}

x - \frac{x + 7}{x + 8} = \frac{x}{x + 8}

What is the answer to (2x^2-5)/(x+1)=x-1 ?
The answer to (2x^2-5)/(x+1)=x-1 is x=2,x=-2
Solve for x: (2x^2-5)/(x+1)=x-1
The solution is x=2,x=-2