What is the answer to (10)/(x^2-3x+5)=x+1 ?

The answer to (10)/(x^2-3x+5)=x+1 is x\approx 2.15091…

Solve for x: (10)/(x^2-3x+5)=x+1

The solution is x\approx 2.15091…

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\frac{10}{x ^{2} - 3 x + 5} = x + 1

x \approx 2.15091 \dots

Solution steps

\frac{10}{x ^{2} - 3 x + 5} = x + 1

Multiply both sides by

x^{2} - 3 x + 5

10 = x (x^{2} - 3 x + 5) + x^{2} - 3 x + 5

Solve

10 = x (x^{2} - 3 x + 5) + x^{2} - 3 x + 5 : x \approx 2.15091 \dots

x \approx 2.15091 \dots

\frac{x + 3}{3} - \frac{4}{x + 2} = \frac{x}{3}

u + 22 = 13 - \frac{18}{u}

1 - \frac{5}{x} = - 4 x

3 - \frac{4 x}{x + 4} = - \frac{4}{x + 4}

\frac{8.4}{4.8} = \frac{6.3}{k}

What is the answer to (10)/(x^2-3x+5)=x+1 ?
The answer to (10)/(x^2-3x+5)=x+1 is x\approx 2.15091…
Solve for x: (10)/(x^2-3x+5)=x+1
The solution is x\approx 2.15091…