What is the answer to 1/(t^2)-16=0 ?

The answer to 1/(t^2)-16=0 is t= 1/4 ,t=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/(t^2)-16=0

\frac{1}{t ^{2}} - 16 = 0

t = \frac{1}{4}, t = - \frac{1}{4}

Decimal Notation

t = 0.25, t = - 0.25

Solution steps

\frac{1}{t ^{2}} - 16 = 0

Multiply both sides by

t^{2}

1 - 16 t^{2} = 0

Solve

1 - 16 t^{2} = 0 : t = \frac{1}{4}, t = - \frac{1}{4}

t = \frac{1}{4}, t = - \frac{1}{4}

Verify Solutions

Find undefined (singularity) points:

t = 0

Combine undefined points with solutions:

t = \frac{1}{4}, t = - \frac{1}{4}

\frac{1}{x - 1} + \frac{2}{x ^{2}} = 0

\frac{1}{x - 1} - 2 = \frac{x}{x - 1}

\frac{3}{5 + m} = \frac{7}{4 - m}

\frac{x}{x + 1} + 4 = \frac{1}{x ^{2} + x}

c, 2 = \frac{12 b ^{4} a ^{2}}{8 c}

What is the answer to 1/(t^2)-16=0 ?
The answer to 1/(t^2)-16=0 is t= 1/4 ,t=-1/4
Solve for t: 1/(t^2)-16=0
The solution is t= 1/4 ,t=-1/4