What is the answer to solvefor t,y=(2t)/(t-1) ?

The answer to solvefor t,y=(2t)/(t-1) is t= y/(y-2);\quad y\ne 2

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solvefor t,y=(2t)/(t-1)

solve for

t, y = \frac{2 t}{t - 1}

t = \frac{y}{y - 2}; y \neq = 2

Solution steps

y = \frac{2 t}{t - 1}

Multiply both sides by

t - 1

y (t - 1) = 2 t

Expand

y (t - 1) : t y - y

t y - y = 2 t

Move

y

to the right side

t y = 2 t + y

Move

2 t

to the left side

t y - 2 t = y

Factor

t y - 2 t : t (y - 2)

t (y - 2) = y

Divide both sides by

y - 2; y \neq = 2

t = \frac{y}{y - 2}; y \neq = 2

\frac{8}{x - 3} = \frac{6}{15}

y, x = \frac{km}{y - p}

\frac{3}{x - 2} = \frac{8}{x + 6}

\frac{x}{x + 1} - 2 = \frac{6}{x - 5}

- \frac{3 x}{x - 5} - 4 = - \frac{1}{x - 5}

What is the answer to solvefor t,y=(2t)/(t-1) ?
The answer to solvefor t,y=(2t)/(t-1) is t= y/(y-2);\quad y\ne 2